a couple plans to have three children. what is the probability that This is a topic that many people are looking for. bluevelvetrestaurant.com is a channel providing useful information about learning, life, digital marketing and online courses …. it will help you have an overview and solid multi-faceted knowledge . Today, bluevelvetrestaurant.com would like to introduce to you In a family with 3 children what is the probability to have one girl. Following along are instructions in the video below:
Todays video going to be about genetics and flow of probability. And todayss question is if a family has three children. What is the probability that they have and first question.
Exactly one go and second question at most two goals and if you think that you can answer. These questions you might stop video here try to solve this problem on your own and then you can run video again. And you can compare your answer with my answer.
And explanation. So lets answer. The first question first and lets count.
How many different grounds. We might have in the family that may have three children and the first variant can be when the family would have all three children boys.
So this would be boy boy and boy another one can be when there can be two boys and one girl and this can be boy boy. And go another variant can be boy go boy. And another one when the first child is go.
And then boy and boy also this family may have two children that is girls and one child. That is boy. So where as possible here you go and boy another one can be a girl boy thank you and the last one can be boy and go and go and also family might have three children that is girls.
So this would be go go and so lets count. How many around this family would have so one two three four five six seven eight eight were rams and now lets count how many variants exist. Where exactly one go present.
So we dont have here any girls and here. We would have one go so.
This one variant and here would be second to around here would be sewed variant and all the following here. We would have two goes to goes here and here and here. We would have all three girls.
So we have one two and three out of total eight. So the answer for the group first question would be three out of eight and second question at most tools and lets do counting once again so once again. We have the same table.
And lets count this time. So here is the first warrant where all the children boys would meet our requirements. Because we dont have the lowest extreme.
We have only maxim extreme that is two goals so we have to circle. This warrant.
So this would be the first variant and this also meet our requirements. We have here only one goal and here. We also have only one goal and here and here.
We have two goals that also meets our requirement and here and here because our question was at most two jaws. So all this seven variants out of eight would meet our requirement. So the answer for the second question would be seven out of eight would meet requirements of this question.
So seven out of eight possibilities. Exist. That this family would have maximum two goes.
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